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Place an isosceles triangle with a base of 60 units and a hight of 50 units in the coordinate plane

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To place an isosceles triangle with a base of 60 units and a height of 50 units on the coordinate plane, we can start by choosing a point as the vertex of the triangle. Let's use the origin (0, 0) as the vertex.

Next, we can plot the other two vertices based on the given dimensions. Since the base is 60 units, we can place one of the other vertices at (-30, 0) since the origin is the midpoint of the base.

Lastly, since the height of the triangle is 50 units, we can place the final vertex at (0, 50).

So, the coordinates of the three vertices of the isosceles triangle with a base of 60 units and a height of 50 units are:
Vertex 1: (0, 0)
Vertex 2: (-30, 0)
Vertex 3: (0, 50)
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