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A simple random sample of 70 items from a population with 8 resulted in a sample mean of 35.

Provide a 90%,95%,99% confidence interval for the population mean.

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Final answer:

To calculate the confidence intervals, use the sample mean of 35 and the known population standard deviation of 8. The 90%, 95%, and 99% confidence intervals are calculated using their respective Z-values, resulting in intervals of (33.43, 36.57), (33.13, 36.87), and (32.55, 37.45) respectively.

Step-by-step explanation:

To provide a 90%, 95%, and 99% confidence interval for the population mean based on a sample mean of 35 derived from a simple random sample of 70 items, and assuming the population has a known standard deviation of 8, we can use the following formula for each confidence interval:

Confidence Interval = Sample Mean ± (Z-value * (Population Standard Deviation / √n))

Where Ýan is the square root of the sample size (n=70).

First, we need to find the Z-values corresponding to the required confidence levels. Relevant Z-values for the confidence levels are approximately:

  • 1.645 for 90% confidence
  • 1.960 for 95% confidence
  • 2.576 for 99% confidence

Now, we calculate the error bound (EBM) using the formula EBM = Z-value * (Population Standard Deviation / √n).

For 90% confidence interval:

EBM = 1.645 * (8 / √70)

Substituting the values, we get EBM90 = 1.57

So, the 90% confidence interval is (35 - 1.57, 35 + 1.57) or (33.43, 36.57).

For 95% confidence interval:

EBM = 1.960 * (8 / √70)

Substituting the values, we get EBM95 = 1.87

So, the 95% confidence interval is (35 - 1.87, 35 + 1.87) or (33.13, 36.87).

For 99% confidence interval:

EBM = 2.576 * (8 / √70)

Substituting the values, we get EBM99 = 2.45

So, the 99% confidence interval is (35 - 2.45, 35 + 2.45) or (32.55, 37.45).

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