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Select the quotient of (8x³ +22x² - 163x-44) (x+6)-¹.

A) 8x²-26x-7
B)8x²-26x-7-6
c) 8x² +26x+7-46
D) 8x² -26x+7-6

1 Answer

2 votes

The quotient of 8x³ + 22x² - 163x - 44/x+6 is

8x² - 26x - 7 - (2/x+6) option D is correct.

How polynomial divided by a factor.

Given

8x³ + 22x² - 163x - 44* (x+6)⁻¹

Let's use polynomial long division or synthetic division.

The dividend is 8x³ + 22x² - 163x - 44

The divisor is x+6

8x² - 26x - 7

_____________________

x + 6 | 8x³ + 22x² - 163x - 44

-(8x³ + 48x²)

________________

-26x² - 163x

+(26x² + 156x)

_______________

-7x - 44

+(7x + 42)

________

-2

So, the quotient is 8x² - 26x - 7 with a remainder of -2.

Therefore, 8x³ + 22x² - 163x - 44/x+6 = 8x² - 26x - 7 - (2/x+6).

Complete question

Select the quotient of (8x³ +22x² - 163x-44) (x+6)-¹. A) 8x²-26x-7 B)8x²-26x-7-6 c-example-1
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