Substituting x=2 and y=1 into the equation
results in
. As the equation holds true, (2,1) is a solution.
To check if the point (2,1) is a solution to the equation
, substitute
and
into the equation. Begin by replacing \(x\) with \(2\) and
with
:
![\[3(2) - 2(1) = 6 - 2 = 4\]](https://img.qammunity.org/2024/formulas/mathematics/high-school/c6ldmbqqetn5uzki97znug4vk78dnn6d3q.png)
Upon calculation, the equation simplifies to
. Since the left-hand side (LHS) equals the right-hand side (RHS), the point (2,1) satisfies the equation. Therefore, (2,1) is indeed a solution to
confirming that when
and
, the equation holds true.
completed question:
"Given the equation
, determine whether the point (2,1) is a solution to the equation. If yes, verify by substituting the x-coordinate as
and the y-coordinate as
into the equation and check whether the resulting equation holds true."