Question

Sergio tiene dos cubos. Cada uno es 2cm más alto que el anterior. El cubo más grande tiene la misma altura que una torre construida con los dos cubos más pequeños. Qué altura tendría una torre de los cinco cubos?

Answer 1

Where the above conditions are given, the height of a tower made from the five cubes would be: 50 cm

Let the height of the smallest cube be = x

Height of each of the other four cubes will be (x+2), (x+4), (x+6), and (x+8). Because each cube, as it is given, is 2cm higher than the previous one.

It says that the largest cube is the same height as the tower build of the two smallest cubes.

(x+8) = x + (x+2)

or x + 8 = 2x +2

rearranged, (2x-x) = 8–2 =6

x = 6

Height of the tower built from placing all 5 cubes on top of each other will be:

6 + (6+2) + (6+4) + (6+6) + (6+8)

= 6+ 8 + 10 + 12 + 14

= 50 cm.

Hence, the height of a tower made from the five cubes would be: 50 cm

Full Question:

Although part of your question is missing, you might be referring to this full question:

Sergio has five cubes. Each one is 2cm higher than the previous one. The largest cube is the same height as a tower built from the two smallest cubes. How tall would a tower of five cubes be?