Question

an object travels around a 120m radius circular path at a constant 70 m/s. the centripetal force on the object is 3.5 x 10 to the 4 power N. what is the mass of the object

Answer 1

`{\boxed{\sf{Mass \ of \ the \ object \approx 857.14 \ kg}}}`

Step-by-step explanation:

centripetal force is given by,

`F_c = ( mv^2 )/(r)`

where,

`F_c` = Centripetal force

m = mass of the body

v = speed or velocity

According to the given question we have, an object travels around a 120m radius (r) circular path at a constant 70 m/s. Centripetal force on the object ,
`(F_c) = 3.5 * 10^4 \ N`

Plugging the required values in the above formula, we have

`\sf 3.5 * 10^4 = (m ( 70^2))/(120)`

`\sf 3.5 * 10^4 = (m (4900))/(120)`

`\sf 3.5 * 10^4 * 120 = m(4900)`

`\sf 420 * 10^4 = m(4900)`

`\sf m = \frac {420 * 100000}{4900}`

`\sf m = (4,200,000)/(4900)`

`{\boxed{\sf{m \approx 857.14 \ kg}}}`

• Hence, the mass of the object is approximately 857.14 kg