Question

In a certain Algebra 2 class of 20 students, 5 of them play basketball and 6 of them play baseball. There are 2 students who play both sports. What is the probability that a student chosen randomly from the class plays basketball or baseball?

Answer 1

To find the probability that a student chosen randomly from the class plays basketball or baseball, we can use the principle of inclusion-exclusion. The probability can be calculated as 9/20.

Step-by-step explanation:

To find the probability that a student chosen randomly from the class plays basketball or baseball, we can use the principle of inclusion-exclusion. Let's denote the event that a student plays basketball as A and the event that a student plays baseball as B. We want to find P(A ∪ B), which can be calculated using the formula P(A ∪ B) = P(A) + P(B) - P(A ∩ B).

Given that there are 5 students who play basketball, 6 students who play baseball, and 2 students who play both sports, we can substitute these values into the formula: P(A ∪ B) = P(A) + P(B) - P(A ∩ B) = 5/20 + 6/20 - 2/20 = 9/20. Therefore, the probability that a randomly chosen student plays basketball or baseball is 9/20.