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What is the approximate standard deviation for 10, 20, 12, 14, 12, 27, 88, 2, 7, 30

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Final answer:

The approximate standard deviation of the set of numbers 10, 20, 12, 14, 12, 27, 88, 2, 7, and 30 is calculated to be around 24.7.

Step-by-step explanation:

To find the approximate standard deviation for the given set of numbers: 10, 20, 12, 14, 12, 27, 88, 2, 7, and 30, we'll follow these steps:

  1. Calculate the mean of the data set.
  2. Subtract the mean from each data point and square the result.
  3. Find the average of these squared differences.
  4. Take the square root of this average to get the standard deviation.

Let's calculate:

Mean (μ) = (10 + 20 + 12 + 14 + 12 + 27 + 88 + 2 + 7 + 30) / 10 = 222 / 10 = 22.2

Next, we calculate the squared differences from the mean:
(10 - 22.2)^2 = 148.84, (20 - 22.2)^2 = 4.84, (12 - 22.2)^2 = 104.04, (14 - 22.2)^2 = 67.24, (12 - 22.2)^2 = 104.04, (27 - 22.2)^2 = 23.04, (88 - 22.2)^2 = 4339.24, (2 - 22.2)^2 = 408.04, (7 - 22.2)^2 = 230.04, (30 - 22.2)^2 = 60.84.

The sum of these squared differences is 5489.20. Since we're looking for a sample standard deviation and not the population standard deviation, we divide by N-1 (which is 10 - 1 = 9):

Variance (σ^2) = 5489.20 / 9 ≈ 609.9111

Finally, take the square root to find the standard deviation:

Standard deviation (σ) = √609.9111 ≈ 24.7

Therefore, the approximate standard deviation of the data set is 24.7.

User Ashok Goli
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