Jacy's statement that f(x) = 4|x – 1| and f(x) = |4x – 1| have the same graph is false
Hwo to determine the true statement
From the question, we have the following parameters that can be used in our computation:
f(x) = 4|x – 1| and f(x) = |4x – 1|
Opening the bracket of f(x) = 4|x – 1|, we have
f(x) = |4x – 4|
By comparison, we have that
f(x) = |4x – 4| and f(x) = |4x – 1| are not the same
Hene, Jacy's statement about the functions is false