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If CD equals, 30CD=30, D, E, equals, 26DE=26, and G, H, equals, 39GH=39, find the length of start overline, F, G, end overline

FG. Round your answer to the nearest tenth if necessary. Figures are not necessarily drawn to scale.

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the length of FG is approximately 20.51 units (rounded to the nearest tenth).


From the diagram, we see that triangles CDE and FGH are similar right triangles. This means that corresponding side lengths are proportional. We are given that DE = 26 and GH = 39, and we want to find FG. Setting up the proportion of corresponding side lengths, we get:

DE/GH = FG/CD

Substituting the known values, we get:

26/39 = FG/30

Cross-multiplying, we get:

26 * 30 = 39 * FG

Solving for FG, we get:

FG = (26 * 30) / 39

FG ≈ 20.51

Therefore, the length of FG is approximately 20.51 units (rounded to the nearest tenth).


The probable question can be: If CD=30,DE=26 , and GH=39 , find the length of overline FG. Round your answer to the nearest tenth if necessary. Figures are not necessarily drawn to scale.

If CD equals, 30CD=30, D, E, equals, 26DE=26, and G, H, equals, 39GH=39, find the-example-1
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