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Given\ \csc \theta =\frac{17}{15},\ \determind\ the\ value\ for\ "a"\ and\ "b"\ in\ \cos \theta =\frac{a}{b}

User Alfah
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To find the values of a and b in the equation cos theta = a/b, use the given information that csc theta = 17/15. Rewrite the equation as 1/sin theta = 17/15 and solve for sin theta. Then use the identity sin^2 theta + cos^2 theta = 1 to find cos theta. Finally, take the square root to find the values for a and b.

To find the value of a and b in the equation cos θ = a/b, we need to use the given information that csc θ = 17/15.

Since csc θ = 1/sin θ, we can rewrite the equation as 1/sin θ = 17/15. To solve for sin θ, we can take the reciprocal of both sides, giving us sin θ = 15/17.

Now we can find cos θ using the identity sin^2 θ + cos^2 θ = 1. Plugging in the values, we have (15/17)^2 + cos^2 θ = 1. Solving for cos^2 θ, we get cos^2 θ = 1 - (15/17)^2.

Finally, taking the square root of both sides, we find cos θ = ± sqrt(1 -(15/17)^2). Therefore, a = ± sqrt(1 - (15/17)^2) and b = 1.

User Pinak Gauswami
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