The momentum of segment C, with a mass of 5.0 kg, after the explosion of the 12.0 kg object is determined by subtracting the momenta of segments A and B from the initial momentum.
After the explosion of the 12.0 kg object, the law of conservation of momentum dictates that the total momentum of the system before the explosion must be equal to the total momentum after the explosion. The initial momentum of the 12.0 kg object traveling to the East at 2.00 m/s is given by the product of its mass and velocity, resulting in a momentum vector entirely to the East.
Upon explosion, the three segments A, B, and C inherit portions of the initial momentum. Segment A, with a mass of 4.0 kg, moves in the E20oN direction at a speed of 7.0 m/s. Segment B, with a mass of 3.0 kg, moves in the N30oE direction at 4.0 m/s. To find the momentum of segment C (mass 5.0 kg), we can subtract the individual momenta of A and B from the initial momentum. The vector addition involves combining the magnitudes and considering the angles.
Finally, with the magnitude and direction determined, we find that segment C has a momentum vector resulting from the combination of A and B's momenta. The direction can be specified in terms of the angle it makes with the East direction, and the magnitude can be calculated using vector addition principles.
The probable question maybe:
What is the magnitude and direction of the momentum of segment C, with a mass of 5.0 kg, after the explosion of the 12.0 kg object?