Question

Consider the following code segment.

int x = 0;
x++;
x += 1;
x = x + 1;
x -= -1;
System.out.println(x);
What is printed when the code segment has been executed?
A. 0
B. 1
C. 2
D. 3
E. 4

Answer 1

The code provided in the question increments an integer variable, initially set to 0, in several steps, resulting in the final output of 4 when the variable is printed. So option (E) is correct.

Step-by-step explanation:

The student's question pertains to a simple Java code execution that involves basic arithmetic operations and incrementation of a variable. Initially, x is set to 0. Subsequent lines of the code increment the value of x by 1, using different but functionally identical operations.

x++: Post-increment x by 1, making it 1.

x += 1: Increase x by another 1, making it 2.

x = x + 1: Add 1 to x again, making it 3.

x -= -1: Subtracting a negative is equivalent to addition, so x becomes 4.

After all operations are performed, System.out.println(x) is called, which prints out the current value of x. Hence, the output when the code segment is executed is 4.