Question

In the following expression, j, k, and m are properly declared and initialized int variables.

!((j != k) l l (k <= m))
Which of the following is equivalent to the expression above?
O (j == k) l l (k > m)
O (j == k) && (k >= m)
O (j == k) && (k > m)
O (j == k) l l (k >= m)
O (j != k) && (j <= m)

Answer 1

The equivalent expression is (j == k) && (k >= m).

Step-by-step explanation:

The given expression is !((j != k) l l (k <= m)). To determine the equivalent expression, we can simplify the logical operators one by one:

1. The expression (j != k) is equivalent to (j == k) because it means "j is not equal to k", which is the same as saying "j is equal to k".
2. The expression (k <= m) is equivalent to (k > m) because it means "k is less than or equal to m", which is the same as saying "k is greater than m".
3. Finally, we can combine the simplified expressions to get the equivalent expression: (j == k) && (k > m).

Therefore, the answer is option B: (j == k) && (k >= m).

The question seeks to find an expression equivalent to the given boolean expression !<((j != k) || (k <= m)) in the context of computer programming. We start by applying De Morgan's laws to the original expression which states that !(A || B) is equivalent to !A && !B. In this case, A is (j != k) and B is (k <= m). Thus we get !(j != k) && !(k <= m) which simplifies to (j == k) && (k > m). This is because !(j != k) is equivalent to (j == k), and !(k <= m) is equivalent to (k > m).