Question

Consider the following code segment.

for (int i = 0; i < 5; i++) // Line 1
{
for (int j = 0; j < 5; j++)
{
int k = i + j;
System.out.print(k + " ");
}
}
Which of the following best describes the result of changing i < 5 to i > 5 in line 1?
A. The numbers will be printed in the reverse order as they were in the original code segment because the outer loop will occur in reverse order.
B. Five additional values will be printed because the outer for loop will iterate one additional time.
C. An infinite loop will occur because the termination condition of the loop will never be reached.
D. There will be no change to the program output.
E. Nothing will be printed because the body of the outer for loop will not execute at all.

Answer 1

Changing the condition in the outer loop from i < 5 to i > 5 will result in no output being printed, as the loop's initial condition is false and the body of the loop will not execute at all.

Step-by-step explanation:

When the condition in Line 1 of the provided code segment is changed from i < 5 to i > 5, the initialization int i = 0; ensures that the condition i > 5 is false right from the start. Consequently, the outer loop will not execute even once, leading to the result that no output will be printed. This is because the loop's termination condition, i > 5, is immediately false, as i is initialized to 0, which is not greater than 5.

This results in the best description of the outcome as per the given options:

E. Nothing will be printed because the body of the outer for loop will not execute at all.