Question

The following code segment prints one or more characters based on the values of boolean variables b1 and b2. Assume that b1 and b2 have been properly declared and initialized.

if (!b1 || b2)
{
System ("A");
}
else
{
System ("B");
}
if (!(b1 || b2))
{
System ("C");
}
else
{
System ("D");
}
if (b1 && !b1)
{
System ("E");
}
If b1 and b2 are both initialized to true, what is printed when the code segment has finished executing?

Answer 1

When both b1 and b2 are initialized to true, the code segment prints "AD". This is determined by evaluating the given conditional statements sequentially and considering the values of the boolean variables.

Step-by-step explanation:

When both b1 and b2 are initialized to true, let's determine what the code segment will print:

For the first conditional, if (!b1 || b2), since b1 is true, !b1 will be false. However, b2 is also true, making the entire or condition true. Thus, it will execute System("A"); and print "A".

For the second conditional, if (!(b1 || b2)), since both b1 and b2 are true, the condition (b1 || b2) is true, and therefore !(b1 || b2) is false. Hence, it will execute System("D"); and print "D".

In the third conditional, if (b1 && !b1), this is always false because b1 cannot be both true and false at the same time. Therefore, nothing is printed for this condition.

The complete output after the code segment has finished executing is "AD".