Question

A kickball player kicks a ball (m=0.50 kg) horizontally along the ground. Before the kick the speed of the ball is 0 ms⁻¹ and after the kick the speed of the ball is 7 ms⁻¹ (both velocities are in the same direction). The kick lasts 0.1 seconds.

What is the average acceleration of the ball?

Answer 1

The average acceleration of the ball during the kick is 70 m/s², calculated by dividing the change in velocity (7 m/s) by the time over which the change occurs (0.1 s).

Step-by-step explanation:

To calculate the average acceleration of the ball during the kick, we use the formula for acceleration, which is the change in velocity divided by the time it takes for that change to occur. In this case, the change in velocity (Δv) is the final velocity minus the initial velocity. Given that the final velocity is 7 m/s and the initial velocity is 0 m/s, the change in velocity is 7 m/s. The time (Δt) over which this change occurs is 0.1 seconds. The formula for average acceleration (a) is: a = Δv / Δt Plugging in the values: a = (7 m/s - 0 m/s) / 0.1 s = 70 m/s² So the average acceleration of the ball during the kick is 70 m/s².