Question

At 6 s into a run, a football player is traveling at 6 m/s. 7 seconds later, the player is traveling at -3 m/s. The acceleration of the football player is ______.

Answer 1

The acceleration of the football player can be calculated using the formula a = Δv / Δt, where Δv is -9 m/s and Δt is 7 s, resulting in an acceleration of -1.29 m/s².

Step-by-step explanation:

The question pertains to calculating the acceleration of a football player when given two different velocities at two different times. Acceleration is defined as the change in velocity over time. We can find the acceleration (a) using the formula:

a = Δv / Δt

Where Δv is the change in velocity and Δt is the change in time.

At 6 seconds, the player's velocity (v1) is 6 m/s, and 7 seconds later (at t = 13 seconds), the player's velocity (v2) is -3 m/s. Therefore, the change in velocity (Δv) is:

Δv = v2 - v1 = (-3 m/s) - (6 m/s) = -9 m/s

And the change in time (Δt) is:

Δt = 13 s - 6 s = 7 s

So the acceleration of the player is:

a = Δv / Δt = (-9 m/s) / (7 s) = -1.29 m/s²

The negative sign indicates that the player is decelerating.