Final answer:
The deceleration of a pilot who lands after falling without a parachute can be calculated using the known impact velocity and the distance over which they come to a stop. In the given scenario, assuming an impact velocity of 54 m/s and a stopping distance of 3 m, the pilot's deceleration would be -243 m/s².
Step-by-step explanation:
The question asks about the deceleration of a pilot who landed after falling without a parachute during World War II. To calculate the deceleration, we use the formula: deceleration = (final velocity^2 - initial velocity^2) / (2 * distance). Assuming the pilot's final velocity upon impact was 54 m/s and they came to a stop over 3 meters, we can determine the deceleration.
By substituting the known values into the formula, we can determine the deceleration: deceleration = (0 - 54^2 m/s) / (2 * 3 m) = -1458 m/s² / 6 m = -243 m/s². Therefore, the pilot's deceleration would be -243 m/s². It is important to note that the minus sign indicates a decrease in speed (deceleration). In reality, the actual deceleration might differ due to factors like drag resistance and the density of the foliage or snow.