Final answer:
The heat load generated by an amplifier with a 65% efficiency rating that draws 7 amperes at 120 VAC is calculated to be 294 watts. The power used is determined and then multiplied by the percentage of power lost as heat (35%).
Step-by-step explanation:
To calculate the heat load generated by an amplifier with an efficiency rating of 65% that draws 7 amperes at 120 VAC, we'll first determine the total power used by the amplifier and then calculate the amount of power that is wasted as heat due to inefficiencies.
The total power (P) drawn by the amplifier is given by the product of the current (I) and voltage (V):
P = I × V
P = 7 A × 120 V
P = 840 W (watts)
Next, since the efficiency (η) is 65%, only 65% of the total power is used for its intended purpose, and the remaining 35% is dissipated as heat. Therefore, the heat load (Pheat) will be:
Pheat = (100% - η) × P
Pheat = (100% - 65%) × 840 W
Pheat = 35% × 840 W
Pheat = 0.35 × 840 W
Pheat = 294 W
So, the heat load generated by the amplifier is 294 watts.