Question

A chemist carries out reactions of barium and barium nitride, Ba₃N₂.

Reaction 1 Barium is reacted with water.
Reaction 2Barium nitride is reacted with water, forming an alkaline solution and an alkaline gas.

Barium is reacted with an excess of oxygen at 500°C, forming barium peroxide, BaO₂.
(i) Write equations for Reaction 1 and Reaction 2.
Ignore state symbols.

Answer 1

The balanced equations for the reactions provided are Reaction 1 - Ba + 2 H2O → Ba(OH)2 + H2, and Reaction 2 - Ba3N2 + 6 H2O → 3 Ba(OH)2 + 2 NH3. Barium reacts with excess oxygen and forms BaO2.

Step-by-step explanation:

Here are the balanced chemical equations for the reactions of barium and barium nitride with water, omitting state symbols as requested:

Reaction 1: Barium reacted with water is represented by the equation:

Ba + 2 H₂O → Ba(OH)₂ + H₂⁺

Reaction 2: Barium nitride reacted with water, forming an alkaline solution, and ammonia gas is represented by the equation:

Ba₃N₂ + 6 H₂O → 3 Ba(OH)₂ + 2 NH₃⁺

When barium is reacted with an excess of oxygen at 500°C forming barium peroxide, the equation is:

2 Ba + O₂ → 2 BaO₂