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A lawyer owns 4 pairs of pants, 5 dress shirts and 6 ties. How many days can the lawyer go without wearing the same combination of three items?

A. 26
B. 34
C. 15
D. 120

User Hagen
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1 Answer

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Final answer:

The correct answer is option D, 120 different combinations of pants, dress shirts, and ties can be made, allowing the lawyer to go 120 days without repeating a combination.

Step-by-step explanation:

The correct answer is option D. To determine how many different combinations of three items (pants, dress shirts, and ties) can be made, we use the basic principle of counting. For each pair of pants, the lawyer can choose from 5 different dress shirts. For each combination of pants and shirt, there are 6 choices of ties. Therefore, the total number of combinations is the product of the number of choices for each item:

Number of combinations = (Number of pants) × (Number of shirts) × (Number of ties)

Number of combinations = 4 × 5 × 6

Number of combinations = 20 × 6

Number of combinations = 120

So the lawyer can go 120 days without wearing the same combination of pants, shirt, and tie.

User Golam
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