Question

The graph above shows velocity v as a function of time t for a 0.50 kg object traveling along a straight line. The graph has three segments labeled 1, 2, and 3. A rope exerts a constant force of magnitude FT on the object along its direction of motion the whole time. During segment 2 only, a frictional force of magnitude Ff is also exerted on the object.

Which of the following expressions correctly relates the magnitudes Ff and FT and why?
A) Ff < FT
B) Ff = FT
C) FT < Ff < 2FT
D) Ff = 2FT

Answer 1

The relationship between frictional force and tension force can be understood through Newton's second law when an object is at rest or moving with a constant velocity. Without the graph or specific details of the velocity changes, the exact relationship between Ff and FT cannot be determined.

Step-by-step explanation:

The question pertains to the concepts of Newton's second law of motion and the forces acting on an object in motion. The key detail provided is the equality of tension in the rope and the weight of the object when it is held at rest, resulting in a net force of zero.

This concept is also relevant when analyzing the velocity vs. time graph of an object where different forces, including tension, gravitational force, or frictional force, affect the object's motion. In this scenario, when there is no change in velocity during segment 2 of the graph, the force of tension (FT) is likely counteracted by the frictional force (Ff), resulting in no acceleration and implying that Ff could be equal to FT. However, without the graph or specific information about the velocity changes, it is not possible to definitively conclude the relationship between Ff and FT.