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How many moles of CCl₄ are present in 118. g of carbon tetrachloride?

A. 0.839
B. 1.19
C. 0.538
D. 1.30
E. 0.767

User Kaklon
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1 Answer

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Final answer:

To find the number of moles of CCl4 present in 118 g of carbon tetrachloride, divide the mass of CCl4 by its molar mass. The answer is 0.767 moles.

Step-by-step explanation:

To find the number of moles of CCl4 present in 118 g of carbon tetrachloride, we need to use the molar mass of CCl4. The molar mass of CCl4 is 12.011 g/mol for carbon and 35.453 g/mol for chlorine. Adding these atomic masses together gives us a molar mass of 153.823 g/mol for CCl4.

Now we can use the given mass of CCl4 and the molar mass to find the number of moles. We divide the mass of CCl4 by its molar mass: 118 g CCl4 / 153.823 g/mol CCl4 = 0.767 mol CCl4.

Therefore, there are 0.767 moles of CCl4 present in 118 g of carbon tetrachloride. So the answer is E. 0.767.

User Artem Kovalov
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