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Analysis of a sample of a covalent compound showed that it contained 14.4% hydrogen and 85.6% carbon by mass. What is the empirical formula for this compound?

A. CH
B. CH₂
C. CH₃
D. C₂H₄
E. C₂H₅

1 Answer

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Final answer:

The empirical formula of a compound with 14.4% hydrogen and 85.6% carbon by mass is CH2. This is found by converting percentages to moles, dividing by the smallest mole value, and simplifying to the smallest whole number ratio.

Step-by-step explanation:

To find the empirical formula of a compound with given mass percentages of its constituent elements, we must convert these percentages to moles, then simplify the ratios. In the case of a compound with 14.4% hydrogen and 85.6% carbon, we first assume a 100 g sample to bypass the conversion to grams. Doing so, we'd have 14.4 g of hydrogen and 85.6 g of carbon.

Since the atomic mass of hydrogen (H) is approximately 1 g/mol and that of carbon (C) is about 12 g/mol, we can now calculate the moles of each:

  • Hydrogen: 14.4 g ÷ 1 g/mol = 14.4 moles
  • Carbon: 85.6 g ÷ 12 g/mol = 7.13 moles

Next, we divide by the smallest number of moles to get the simplest whole number ratio:

  • Hydrogen: 14.4 moles ÷ 7.13 moles ≈ 2
  • Carbon: 7.13 moles ÷ 7.13 moles = 1

Therefore, the empirical formula of the compound is CH2.

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