Final answer:
The broadcast address for the 192.168.50.155/20 network is 192.168.63.255. This is calculated by determining the subnet mask from the /20 prefix, identifying the network increment, and setting all host bits to 1.
Step-by-step explanation:
The question asks for the broadcast address of the network 192.168.50.155/20. To determine the broadcast address, we must first understand the subnet mask associated with the /20 subnet. A /20 subnet has 20 bits set to 1 in the subnet mask, which means the first 20 bits of the IP address define the network, and the remaining 12 bits (32-20) are used for host addresses within that network.
The subnet mask in binary form would look like: 11111111.11111111.11110000.00000000. In decimal, this is 255.255.240.0. Thus, the network increments in blocks of 16 in the third octet (since 24 = 16). The network address for 192.168.50.155 with a /20 mask would thus be the nearest previous block of 16, which is 192.168.48.0.
The broadcast address is found by setting all host bits in the IP address to 1. The last address in the 192.168.48.0/20 network range would then be 192.168.63.255 (48 + 15 = 63 for the third octet, and all ones in the fourth octet).
So, the correct answer is c. 192.168.63.255.