356,050 views
2 votes
2 votes
Manuel watered all the flowers at a business park. While watering, he noticed the daisies had been planted in groups of 11 and the lilies had been planted in groups of 12. If Manuel watered the same number of each flower, what is the minimum number of each that he must have watered?

User Tate Thurston
by
2.7k points

1 Answer

14 votes
14 votes

Answer:

The minimum number of daisies and lilies that Manuel must have watered is 11.

Explanation:

To find the minimum number of daisies and lilies that Manuel must have watered, we need to find the least common multiple (LCM) of 11 and 12. The LCM of two numbers is the smallest positive integer that is a multiple of both numbers.

To find the LCM of 11 and 12, we can list the multiples of each number and find the smallest number that appears in both lists. The multiples of 11 are 11, 22, 33, 44, 55, 66, 77, 88, 99, 110, 121, etc. The multiples of 12 are 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, etc.

We can see that the smallest number that appears in both lists is 11, which is the LCM of 11 and 12. Therefore, the minimum number of daisies and lilies that Manuel must have watered is 11. If he watered the same number of each flower, he must have watered at least 11 daisies and 11 lilies.

User RusHughes
by
3.4k points