Final answer:
The correct answer is option One-way ANOVA Table, used to determine if there are significant differences between the means of four treatments.
Step-by-step explanation:
The correct answer is option One-way ANOVA Table. In your experiment with four treatments and seven blocks, an analysis of variance (ANOVA) test is used to determine if there are any statistically significant differences between the means of the four treatments.
Given the F statistic of 2.2303 and the p-value of 0.0054 at a significance level of 5 percent, you would compare the F statistic to a critical value from an F-distribution table with degrees of freedom (df) for between treatments (k-1) and within treatments (n-k), where k is the number of treatments and n is the total number of observations.
The ANOVA table helps you calculate the mean squares (MS) by dividing each sum of squares (SS) by its respective df. For SSbetween with df = k-1, and for SSwithin with df = n – k.
To complete the ANOVA table, you would calculate the mean squares for between (MSbetween) and within (MSwithin), then use these values to find the F statistic.
Subsequently, you use the p-value along with the given significance level to decide whether to reject the null hypothesis. If the p-value is less than the significance level (0.05), you would reject the null hypothesis, suggesting at least two group means are significantly different.
F statistic and p-value are compared against critical values to decide on the null hypothesis at a 5 percent significance level.