Question

Give the complete ionic equation for the reaction that occurs when aqueous solutions of copper(II) sulfate and barium chloride are mixed.

o Cu²⁺(aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2Cl⁻(aq) -> CuCl₂(aq) + Ba²⁺(aq) +SO₄²⁻(aq)
o Cu²⁺(aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2Cl⁻(aq) -> Cu²⁺(aq) + 2Cl⁻(aq) + BaSO₄(s)
o CuSO₄(aq) + BaCl₂(aq) -> BaSO₄(s) + CuCl₂(aq)
o Cu²⁺(aq) + 2Cl⁻(aq) -> CuCl₂(aq)
o Ba²⁺ (aq) + SO₄²⁻(aq) -> BaSO₄(s)

Answer 1

The complete ionic equation of copper(II) sulfate and barium chloride is Cu²⁺(aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2Cl⁻(aq) → Cu²⁺(aq) + 2Cl⁻(aq) + BaSO₄(s), and the net ionic equation is Ba²⁺ (aq) + SO₄²⁻(aq) → BaSO₄(s).

Step-by-step explanation:

When aqueous solutions of copper(II) sulfate and barium chloride are mixed, a precipitation reaction occurs. The complete ionic equation for this reaction is:

Cu²⁺(aq) + SO₄²⁻ (aq) + Ba²⁺ (aq) + 2Cl⁻(aq) → Cu²⁺(aq) + 2Cl⁻(aq) + BaSO₄(s)

However, since the copper(II) ions and chloride ions are spectator ions and do not participate in the formation of the precipitate, they can be omitted from the net ionic equation, which simply shows the formation of barium sulfate precipitate:

Ba²⁺ (aq) + SO₄²⁻(aq) → BaSO₄(s)