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How many moles of gas are there in 36.5L flask at 68.0 degree celsius and 672mmHg

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Final answer:

To find the number of moles of gas in a 36.5L flask at 68.0 degrees Celsius and 672mmHg, convert the temperature to Kelvin and the pressure to atmospheres, then use the Ideal Gas Law, PV = nRT, with the value of R as 0.0821 L×atm/(K×mol), to solve for n (number of moles).

Step-by-step explanation:

To calculate the number of moles of gas in a 36.5L flask at 68.0 degrees Celsius and 672mmHg, we can use the Ideal Gas Law: PV = nRT. However, we need to adjust the pressure to the atmosphere and the temperature to Kelvin.

First, convert the temperature to Kelvin: T(K) = 68.0 °C + 273.15 = 341.15 K.
Second, convert the pressure to atmospheres: P(atm) = 672 mmHg / 760 mmHg(atm) ≈ 0.885 atm.

Now, using R, the ideal gas constant in the units L × atm/(K × mol), which is 0.0821 L×atm/(K×mol), the equation becomes:

n = PV / RT
n = (0.885 atm × 36.5 L) / (0.0821 L×atm/(K×mol) × 341.15 K)

After calculating, we find the number of moles present in the flask.

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