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The reaction of 25mL of N₂of gas with 75mL of H2 gas will produce _________mL of ammonia, NH₃ if the pressure and temperature are kept constant

N₂(g)+3H₂(g) = 2NH₃(g)

1 Answer

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Final answer:

The reaction of 25 mL of N₂ gas with 75 mL of H₂ gas will produce 50 mL of ammonia, NH₃.

Step-by-step explanation:

The balanced chemical equation for the reaction is:

N₂(g) + 3H₂(g) → 2NH₃(g)

According to Avogadro's law, equal volumes of gaseous N₂, H₂, and NH₃ at the same temperature and pressure contain the same number of molecules. Since one molecule of N₂ reacts with three molecules of H₂ to produce two molecules of NH₃, the volume of H₂ required is three times the volume of N₂ and the volume of NH₃ produced is two times the volume of N₂.

Given that 25 mL of N₂ gas and 75 mL of H₂ gas are used, the volume of ammonia, NH₃, can be calculated as follows:

Volume of NH₃ = 2 times the volume of N₂

= 2 x 25 mL

= 50 mL

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