Final answer:
The molarity of an aqueous solution containing 52.5 g of sucrose in 35.5mL of solution is calculated to be 4.325 M after converting the mass of sucrose to moles and dividing by the volume of the solution in liters.
Step-by-step explanation:
The molarity (M) of an aqueous solution is defined as moles of solute per liter of solution (mol/L). To find the molarity of the sucrose solution, we need to convert the mass of sucrose to moles and then divide by the volume of the solution in liters.
Firstly, the molar mass of sucrose (C₁₂H₂₂O₁₁) is 342.297 g/mol. So, the number of moles of sucrose in 52.5 g is given by:
Number of moles = 52.5 g / 342.297 g/mol = 0.1534 mol (rounded to 4 significant figures).
To find the molarity, we need the volume in liters, hence:
Volume = 35.5 mL = 0.0355 L.
Therefore, the molarity (M) of the sucrose solution is:
Molarity (M) = Number of moles / Volume in liters
Molarity (M) = 0.1534 mol / 0.0355 L = 4.325 M (rounded to 4 significant figures).