Question

If 29.3 mL of a 6.00 M solution of sodium hydroxide, NaOH is diluted to a volume of 200.0 mL by the additional of water, what is the concentration of the dilute solution?

Answer 1

The concentration of the sodium hydroxide (NaOH) solution after dilution to a volume of 200.0 mL is found to be 0.879 M, calculated using the formula M1V1 = M2V2.

Step-by-step explanation:

To calculate the concentration of the dilute solution after the sodium hydroxide (NaOH) has been diluted, we can use the formula M1V1 = M2V2, where M1 and V1 represent the molarity and volume of the initial solution, and M2 and V2 represent the molarity and volume of the final solution. In this case:

• M1 (initial molarity) = 6.00 M
• V1 (initial volume) = 29.3 mL
• V2 (final volume) = 200.0 mL

We need to find M2. So, the equation becomes:

6.00 M × 29.3 mL = M2 × 200.0 mL

Now, solving for M2:

M2 = (6.00 × 29.3) / 200.0

M2 = 0.879 M

Therefore, the concentration of the dilute NaOH solution is 0.879 M.