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How many grams of H₃PO₄ are in 175 mL of a 3.50 M solution of H₃PO₄ ? The molar mass of H₃PO₄ is 97.99 g/mol

User Sebdelsol
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Final answer:

To calculate the grams of H₃PO₄ in a 175 mL solution at 3.50 M concentration, multiply the volume in liters by the molarity and the molar mass, which equals 60.10 grams.

Step-by-step explanation:

To find out how many grams of H₃PO₄ are in 175 mL of a 3.50 M solution of H₃PO₄, you'll need to use the formula:

mass (g) = molarity (M) × volume (L) × molar mass (g/mol)

Firstly, convert the volume from milliliters to liters by dividing by 1000:

  • 175 mL = 0.175 L

Next, use the formula with the given values:

  • molarity (M) = 3.50 M
  • volume (L) = 0.175 L
  • molar mass (H₃PO₄) = 97.99 g/mol

Mass of H₃PO₄ = 3.50 M × 0.175 L × 97.99 g/mol = 60.0965 g

Therefore, 175 mL of a 3.50 M H₃PO₄ solution contains 60.10 grams of H₃PO₄.

User Chhaya
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