36.2k views
2 votes
Calculate the de Broglie wavelength of an electron traveling at a speed of 3.15x10² ms⁻¹ the mass of an electron is 9.11x10⁻²⁸ grams and 1 J= kg m²s⁻²

User Tombreit
by
8.0k points

1 Answer

2 votes

Final answer:

The de Broglie wavelength of an electron traveling at a speed of 3.15x10² m/s is 2.426 x 10^-10 meters.

Step-by-step explanation:

To calculate the de Broglie wavelength of an electron traveling at a speed of 3.15x10² ms⁻¹, we can use the de Broglie wavelength equation:

λ = h / (mv)

Where λ is the wavelength, h is Planck's constant (6.626 x 10^-34 Js), m is the mass of the electron (9.11 x 10^-31 kg), and v is the velocity of the electron.

Plugging in the values, we get:

λ = (6.626 x 10^-34 Js) / ((9.11 x 10^-31 kg) * (3.15 x 10² ms⁻¹))

λ = 2.426 x 10^-10 meters

User James Wheare
by
7.8k points