Using the synthetic division and remainder theorem,
.
Calculating polynomial function using synthetic division and remainder theorem.
We are to divide the function
using synthetic division method.
We will have to take the constant of the divisor with an opposite sign and also write the coefficients of the dividends to the right. i.e.
|| x⁴ x³ x² x¹ x⁰
-15 || 1 -4 -19 -46 120
We will write the first coefficient without changes:
|| x⁴ x³ x² x¹ x⁰
-15 || 1 -4 -19 -46 120
The next step is to multiply the entry in the left part of the table by the last entry in the result row, then add the result gotten to the next coefficient of the dividend, and write down the sum.
-15 || 1 -4 -19 -46 120
|| (-15) × (1) = -15
1 (-4) + (-15) = -19
We will repeat the same process for the remaining values, and we have:
-15 || 1 -4 -19 -46 120
|| -15 (-15) × (-19) = 285
1 -19 (-19) + 285 = 266
-15 || 1 -4 -19 -46 120
|| -15 285 (-15) × (266) = -3990
1 -19 266 (-46)+(-3990) = -4036
-15 || 1 -4 -19 -46 120
|| -15 285 -3990 (-15) × (-4036) = 60540
1 -19 266 -4036 (120)+(60540) = 60660
Now, the complete table is done and have the following resulting coefficients: 1, −19, 266, −4036, 60660. Therefore, the quotient is:
and the remainder is 60660.
We can conclude that using the synthetic division and remainder theorem,
