Final answer:
To balance the chemical equation between H2SO4 and Pb(OH)4, one must ensure equal numbers of each type of atom on both sides of the equation resulting in the balanced equation: H2SO4(aq) + 2 Pb(OH)4(s) → 2 Pb(SO4)2(s) + 4 H2O(l).
Step-by-step explanation:
The question asks to balance the chemical equation for the reaction between sulfuric acid (H2SO4) and lead(IV) hydroxide (Pb(OH)4). The balanced equation for this reaction is:
- Write down the unbalanced equation: H2SO4(aq) + Pb(OH)4(s) → Pb(SO4)2(s) + H2O(l)
- Balance the lead (Pb) atoms by ensuring there is one Pb atom on each side of the equation.
- Balance the sulfate (SO42-) ions by making sure there are two sulfate ions on each side of the equation.
- Balance the hydroxide (OH-) ions by noting that there are four OH groups in Pb(OH)4 and hence there should be four H2O molecules produced.
- Finally, balance the hydrogen (H) atoms and optimize the coefficients to satisfy the stoichiometry of the reaction.
The correct balanced equation is: H2SO4(aq) + 2 Pb(OH)4(s) → 2 Pb(SO4)2(s) + 4 H2O(l)