Question

A waterfall has a height of 1200 feet. A pebble is thrown upward from the top of the falls with an initial velocity of 20 feet

per second. The height, h, of the pebble after t seconds is given by the equation h= -16+201+1200. How long after
the pebble is thrown will it hit the ground? Use a graphing calculator to solve the problem.



Help pleasee asap

Answer 1

Below

Explanation:

h = height = 0 when it hits the ground

sooooo...

0 = -16t^2 + 20t + 1200 <==== you equation ommited the t' s and 20t

Use Quadratic Formula a = -16 b = 20 c = 1200

to find t = 9.3 s