Question

solve, savitri bought a book and a pen. The cost of the pen was 6/10 the cost of the book. If the book costs $20 more than the pen, how much money did savitri pay for both items

Answer 1

Savitri paid a total of $80 for both the book and the pen. To solve this, two equations were set up based on the given relationships and solved sequentially to find the individual prices and total cost.

Step-by-step explanation:

To solve the problem of finding out how much Savitri paid for both a book and a pen, we need to set up equations based on the given information:

• The cost of the pen was 6/10 the cost of the book.
• The book costs $20 more than the pen.

Let's denote the cost of the pen as P and the cost of the book as B. Based on the given info, we can write the following equation:

P = ⅔B ... (1)

Since the book costs $20 more than the pen, the second equation is:

B = P + $20 ... (2)

Substituting equation (1) into equation (2), we get:

B = ⅔B + $20

Multiplying both sides by 10 to clear the fraction, we get:

10B = 6B + $200

This simplifies to:

4B = $200

Dividing both sides by 4, we find the cost of the book:

B = $50

Substituting the value of B back into equation (1), we find the cost of the pen:

P = ⅔ × $50 = $30

To find the total cost spent on both items, we add the cost of the book and the pen:

Total Cost = B + P = $50 + $30 = $80

Savitri paid a total of $80 for both the book and pen.