Final answer:
The voltage drop across two 80-ohm resistors in series with 0.15 A of current flowing through them is 24 V, calculated using Ohm's law (V = IR).
Step-by-step explanation:
The question concerning the voltage drop across two 80-ohm resistors connected in series with 0.15 A flowing through them relates to the concept of series circuits within physics, specifically in the area of electricity and Ohm's law. Four using Ohm's law, the voltage drop (V) across a resistor can be calculated by the formula V = IR, where I is the current and R is the resistance.
For two resistors in series, we simply add their resistances to get the total resistance. In this case, the total resistance is 80 ohms + 80 ohms = 160 ohms. Therefore, the voltage drop is V = 0.15 A × 160 ohms = 24 V. Hence, the correct answer is (b) 24 volts.