51.5k views
1 vote
What is the total resistance of a circuit consisting of two, 8MFD capacitors connected in series at 60HZ?

User Evan Nagle
by
8.3k points

1 Answer

1 vote

Final answer:

The total capacitance of the circuit consisting of two 8MFD capacitors connected in series is 4 MFD.

Step-by-step explanation:

In a series circuit, the total capacitance is given by the reciprocal of the sum of the reciprocals of the individual capacitances. In this case, with two capacitors connected in series, the total capacitance (C_total) is:

C_total = 1/(1/C1 + 1/C2)

Substituting C1 = C2 = 8 MFD (microfarads), we get:

C_total = 1/(1/8 + 1/8) = 1/(1/4) = 4 MFD

Therefore, the total capacitance of the circuit is 4 MFD.

User Abolfazl Mohajeri
by
8.7k points