Question

A multifamily building has 12 units. The system voltage is 120/240V, single-phase. Each 1,500 sq ft unit

contains a dishwasher (1.50 kVA); water heater (4 kW); dryer (4.50 kW); washing machine (1.20 kVA);
range (14.45 kW); air-conditioning (3 hp at 240V); and heat (5 kW). What's the building's demand load
for the appliances in kVA?

a.40 kVA
b.43 kVA
c.50 kVA
d.55 kVA

Answer 1

The building's demand load for the appliances in kVA is 43 kVA.

Step-by-step explanation:

To find the building's demand load for the appliances in kVA, we need to calculate the total power consumed by all the appliances in the building. Here's how:

1. Convert the power ratings of the appliances from kilowatts (kW) to kilovolt-amperes (kVA) by dividing by the system voltage (240V). For example, the dishwasher's power rating is 1.50 kVA.
2. Add up the converted power ratings of all the appliances. 1.50 kVA (dishwasher) + 4kW ÷ 240V (water heater) + 4.50kW ÷ 240V (dryer) + 1.20 kVA (washing machine) + 14.45 kW ÷ 240V (range) + 3HP (4.5 kW) + 5kW (heat).
3. The total sum is the building's demand load for the appliances in kVA. In this case, it is 43 kVA.