Final answer:
The neutral sigma baryon, represented as (uds), decays into a lambda baryon (uds) and a photon, indicating that the sigma is an excited state of the lambda.
Step-by-step explanation:
The quark structure of the neutral sigma baryon (Σ0) can be understood by examining its decay into lambda baryon (Λ0) and a photon (γ). The Σ0 is composed of up (u), down (d), and strange (s) quarks, represented as (uds), having no net electric charge. The decay of the sigma baryon into a lambda baryon can be represented as Σ0 → Λ0 + γ, where the lambda baryon also has a quark composition of (uds). This decay process suggests that the Σ0 is an excited state of the Λ0, with the emission of the photon as a result of the de-excitation process.