Question

The body uses glucose (C6H12O6) as a fuel. The reaction is given by:

C₆H₁₂O₆(aq) + 6O₂(g) → 6CO₂ + 6H₂O(l) ΔH°= -2820 kJ

How many grams of glucose someone who has a mass of 89.3 kg have to burn in order to raise the temperature of their body from 36.1 °C to 39.7 °C? The specific heat capacity of the human body is 3.500 J/g· °C.

Answer 1

You would need to burn approximately 86.10 grams of glucose to raise the temperature of a person's body according to the specific heat capacity of the human body.

Step-by-step explanation:

To calculate the amount of glucose needed to raise the temperature of someone's body, we need to use the specific heat capacity equation.

First, calculate the heat energy needed using the equation Q = mcΔT.

Next, convert the heat energy from J to kJ by dividing by 1000. Finally, use the enthalpy of reaction equation to convert kJ to grams of glucose burned.

For example, if the person has a mass of 89.3 kg, the change in temperature is (39.7 °C - 36.1 °C) = 3.6 °C, and the specific heat capacity of the human body is 3.500 J/g·°C, the heat energy needed is:

Q = (89.3 kg)(3.500 J/g· °C)(3.6 °C) = 1140.12 kJ

Now, using the enthalpy of reaction equation, we can convert the heat energy to grams of glucose burned:

1140.12 kJ x (1 mol C6H12O6 / 2820 kJ) x (180.16 g C6H12O6 / 1 mol C6H12O6) = 86.10 g