Question

A 92.9 g piece of a silver/gray metal is heated to 178.0 °C, and then quickly transferred into 75.0 ml. of water initially at 24.0 °C. After 5 minutes, both the metal and the water have reached the same temperature: 29.7 °C. Determine the specific heat and the identity of the metal.

Answer 1

To determine the specific heat and the identity of the metal, use the equation Q = mcΔT. Calculate the heat gained by the water using the equation Q = mcΔT and solve for the specific heat of the metal. Identify the metal by comparing its specific heat value to known values.

Step-by-step explanation:

To determine the specific heat and the identity of the metal, we can use the equation Q = mcΔT, where Q is the heat absorbed or released by the metal, m is the mass of the metal, c is the specific heat of the metal, and ΔT is the change in temperature. In this case, the metal releases heat to the water, so the heat gained by the water is equal to the heat lost by the metal. We can calculate the heat gained by the water using the equation Q = mcΔT and then solve for the specific heat of the metal using the equation Q = mcΔT. Once we have the specific heat, we can use reference tables to identify the metal based on its known specific heat values.