Question

Glycogen phosphoylase catalyzes the removal of glucose from glycogen. The ΔGo' for this reaction is 3.1 kJ/mol

Part 1: Calculate the raito of [Pi] to [gllucose 1-phosphate] when the reaction is at equilibrium at 298K. (Hint: the removal of glucose units from glycogen does not change the glycogen concentration.)

Answer 1

The ratio of [Pi] to [glucose 1-phosphate] at equilibrium is 15.29.

Step-by-step explanation:

The ratio of [Pi] to [glucose 1-phosphate] at equilibrium can be calculated using the ΔGo' value for the reaction. We can use the formula ΔGo' = -RTln(K), where R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (298 K), and K is the equilibrium constant. Rearranging the equation, we have K = e^(-ΔGo'/RT). Plugging in the values, we get K = e^(-(-3.1*10^3 J/mol)/(8.314 J/mol·K * 298 K)). Simplifying this expression, we find K = 15.29. Since K = [glucose 1-phosphate] / [Pi], we can rearrange the equation to solve for the ratio of [Pi] to [glucose 1-phosphate]. The ratio is therefore [Pi] / [glucose 1-phosphate] = 15.29.