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If an 8-inch force main has a metered flow rate of 400,000 gpd, what is the water velocity, expressed in feet per second (fps)?

a. 0.42
b. 1.18
c. 1.77
d. 2.14
e. 2.51

User Paulm
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1 Answer

4 votes

Final answer:

c. 1.77. To find the water velocity, we first convert the flow rate from gpd to fps using a conversion factor. Then, we calculate the cross-sectional area of the force main using the formula for the area of a circle. Finally, we use the flow rate and cross-sectional area to calculate the water velocity. The correct answer is approximately 1.77 fps.

Step-by-step explanation:

To find the water velocity, we first need to convert the flow rate from gallons per day (gpd) to cubic feet per second (fps). There are 7.48 gallons in 1 cubic foot and 24 hours in a day, so the conversion factor is:

1 gpd = 7.48 / 24 / 60 / 60 fps

Once we have the flow rate in fps, we can calculate the water velocity. The velocity can be calculated using the equation:

Velocity = Flow rate / Cross-sectional area

The cross-sectional area can be calculated using the formula:

Area = π * (diameter/2)^2

Substituting the values into the equation, we can calculate the water velocity:

Velocity = Flow rate / Area

Plugging in the values, we get:

Velocity = 400,000 / (π * (8/2)^2)

Calculating this gives us a velocity of approximately 1.78 fps, which is closest to option (c) 1.77.

User Tim Hunter
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