Final answer:
To produce a 1.0 M solution of KI, mixing 10 mL of 1.0 M HI with 10 mL of 1.0 M KOH will result in a neutralization reaction that produces KI and water. This method assumes both reactants are at the correct concentration and volumes are accurately measured.
Step-by-step explanation:
To produce 20 mL of a 1.0 M solution of KI (potassium iodide), one could mix 10 mL of 1.0 M HI (hydroiodic acid) with 10 mL of 1.0 M KOH (potassium hydroxide). This method uses the principle of neutralization, where an acid reacts with a base to form water and a salt, in this case, KI. The reaction between HI and KOH produces water (H2O) and potassium iodide (KI) as follows:
HI(aq) + KOH(aq) → KI(aq) + H2O(l)
As long as the reactants are at the correct molarity (1.0 M) and volumes are measured accurately, the resulting solution should be approximately 1.0 M KI, without the need for further dilution or concentration. This process is a common practice in chemistry, particularly in the preparation of solutions for various laboratory experiments or titrations, which are quantitative analytical procedures used to determine the concentration of an unknown solution by reacting it with a known concentration of another solution.
Overall, the combination of equimolar solutions of acid and base as described effectively demonstrates the concept of solution preparation through neutralization, a fundamental technique in chemistry.