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Graphing cubic function in y=ax³
plot 5 points, one x=0, 2 above x, and 2 below x

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Final answer:

To graph a cubic function y=ax³, create a table of values with x-values -2, -1, 0, 1, and 2, calculate the corresponding y-values, plot the points on a graph, and draw a smooth curve through them, creating the characteristic shape of the cubic function.

Step-by-step explanation:

To graph a cubic function such as y = ax³, you can begin by choosing x-values and substituting them into the equation to find their corresponding y-values. Start with x=0, for which the value of y will also be 0, since any number raised to the power of 3 and then multiplied by a (where a is a constant) will equal 0 if x=0. Then choose two values of x greater than 0 and two values less than 0. Let's use the points -2, -1, 1, and 2 to plot along with the origin (0,0).

Creating a table of values, with one column for x and one for y, calculate the y-value for each x-value. For example, if a=1 and we've chosen the points mentioned above, our table may look like this:

  • (-2, -8)
  • (-1, -1)
  • (0, 0)
  • (1, 1)
  • (2, 8)

Finally, plot these points on the Cartesian plane and draw a smooth curve through all the points, ensuring that the graph shows the characteristic shape of a cubic function, which rises and falls with no sharp corners. Remember, the exact shape will depend on the value of coefficient 'a' in the original equation.

User Mohamed Khalil
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