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Show how the ratio kcat/KM corresponds to the second-order rate constant for enzyme-substrate combination under circumstances of low substrate concentration.

User Yodahaji
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Final answer:

The kcat/KM ratio represents the second-order rate constant for enzyme-catalyzed reactions at low substrate concentrations, reflecting enzyme efficiency up to a diffusion-limited maximal rate represented by k1.

Step-by-step explanation:

The ratio kcat/KM reflects the efficiency with which an enzyme catalyzes the conversion of substrate (S) to product (P) under conditions where substrate concentration is much lower than the Michaelis constant (KM). This ratio can be seen as a second-order rate constant when [S] << KM, which corresponds to the rate of enzyme-substrate (ES) complex formation leading to product formation. KM itself is derived from a combination of rate constants and reflects how well an enzyme binds a substrate and converts it to product.

The efficiency has an upper limit, described by the rate constant k1, beyond which even better catalysis or tighter substrate binding will not increase the overall reaction rate. This upper limit corresponds to the scenario where the reaction rate only depends on how quickly the enzyme E and substrate S can diffuse together. The perfect enzyme is so efficient that the formation of ES complex to the product occurs as fast as E and S can encounter each other, effectively making the rate constant kcat/KM equal to the diffusion rate constant k1.

User Polara
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